Sir, would you like to discuss about capacitors in parallel
Consider, two identical capacitors. Identical means, they have same plate dimensions, same dielectric material, and same distance
of separation between plates, as shown here. Let them now, move vertically until the top, and bottom edges respectively of their plates
make contact. We will now effectively have a single capacitor of twice the cross sectional area of one of
the original capacitors, but all other properties will remain unchanged. Since, capacitor c equal to epsilon into, a a, by d, where, a a is the area of plate
d is the distance between two parallel plates. And epsilon is the permittivity of the dielectric
Then the new capacitor so formed will have twice the capacitance of one of the original capacitors
The same effect could have been achieved, if we had simply connected the appropriate
plates together by means of a simple electrical connection. In other words, connect them in parallel with each other
Both of the original capacitors have the same capacitance, and this figure is doubled when
they are connected in parallel. Thus, we can draw the conclusion, that with this connection the total capacitance of the
combination is given simply by adding the capacitance values. However, this might be considered as a special case
Let us verify this conclusion by considering the general case of 3 different value capacitors
connected in parallel to a dc supply, of v, volt. Each capacitor will take a charge from the supply according to its capacitance, q1 equals
to v into c1, q2 equals to v into c2, q3 equals to v into c3
But the total charge drawn from the supply must be, q equals q1 plus q2 plus q3
If capacitance of the total system is c, then, total charge, q will equal to v into c thus
v into c, equals to, v into c1 plus, v into c2 plus, v into c3, and dividing this equation
by v, we get, c equals to, c1 plus, c2 plus, c3
This result is exactly the opposite in form to that for resistors in parallel
This result is same as resistors connected in series. If there are more than 3 capacitors, connected in parallel, the expression will be similar
And then, c equals to c1 plus, c2 plus, c3 plus, up to cn
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